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a^2+6a+9=a-10
We move all terms to the left:
a^2+6a+9-(a-10)=0
We get rid of parentheses
a^2+6a-a+10+9=0
We add all the numbers together, and all the variables
a^2+5a+19=0
a = 1; b = 5; c = +19;
Δ = b2-4ac
Δ = 52-4·1·19
Δ = -51
Delta is less than zero, so there is no solution for the equation
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